What are the solutions to the equation x^2-2x-23=0 ?

The solutions to the equation x^2-2x-23=0 are x=1+2sqrt(6),x=1-2sqrt(6)

Find the zeros of x^2-2x-23=0

The zeros of x^2-2x-23=0 are x=1+2sqrt(6),x=1-2sqrt(6)

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x^{2} - 2 x - 23 = 0

x = 1 + 26, x = 1 - 26

Decimal Notation

x = 5.89897 \dots, x = - 3.89897 \dots

Solution steps

x^{2} - 2 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 23) = 46

x_{1, 2} = \frac{- ( - 2 ) \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 6}{2 \cdot 1} : 1 + 26

x = \frac{- ( - 2 ) - 4 6}{2 \cdot 1} : 1 - 26

The solutions to the quadratic equation are:

x = 1 + 26, x = 1 - 26

5 - 5 x^{2} = - 230

2 x^{2} - 15 x + 7 = 0

(x + 4)^{2} - 25 = 0

17 - \frac{1}{9} x = 10

12 - x \cdot x - 12

What are the solutions to the equation x^2-2x-23=0 ?
The solutions to the equation x^2-2x-23=0 are x=1+2sqrt(6),x=1-2sqrt(6)
Find the zeros of x^2-2x-23=0
The zeros of x^2-2x-23=0 are x=1+2sqrt(6),x=1-2sqrt(6)