What are the solutions to the equation 3x^2-8=-2x ?

The solutions to the equation 3x^2-8=-2x are x= 4/3 ,x=-2

Find the zeros of 3x^2-8=-2x

The zeros of 3x^2-8=-2x are x= 4/3 ,x=-2

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3 x^{2} - 8 = - 2 x

x = \frac{4}{3}, x = - 2

Solution steps

3 x^{2} - 8 = - 2 x

Move

2 x

to the left side

3 x^{2} - 8 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 8) = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 \cdot 3}, x_{2} = \frac{- 2 - 10}{2 \cdot 3}

x = \frac{- 2 + 10}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 2 - 10}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 2

- 6 - 3

5 - 4 x = 5 + 4 x

ln (2^{2})

- 7 (- 1 + 3 a) = 5 (3 - 5 a)

4 ∣ 2 x - 7 ∣ + 5 > 19

What are the solutions to the equation 3x^2-8=-2x ?
The solutions to the equation 3x^2-8=-2x are x= 4/3 ,x=-2
Find the zeros of 3x^2-8=-2x
The zeros of 3x^2-8=-2x are x= 4/3 ,x=-2