What are the solutions to the equation 3x^2+6x-72=0 ?

The solutions to the equation 3x^2+6x-72=0 are x=4,x=-6

Find the zeros of 3x^2+6x-72=0

The zeros of 3x^2+6x-72=0 are x=4,x=-6

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3 x^{2} + 6 x - 72 = 0

x = 4, x = - 6

Solution steps

3 x^{2} + 6 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 72 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 72) = 30

x_{1, 2} = \frac{- 6 \pm 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 30}{2 \cdot 3}, x_{2} = \frac{- 6 - 30}{2 \cdot 3}

x = \frac{- 6 + 30}{2 \cdot 3} : 4

x = \frac{- 6 - 30}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

x = 4, x = - 6

15 x^{2} - 4 x y - 4 y^{2}

3 x^{2} + x = 2

(\frac{3}{5})^{- 1}

(x - 1)^{\frac{7}{2}} - (x - 1)^{\frac{3}{2}}

What are the solutions to the equation 3x^2+6x-72=0 ?
The solutions to the equation 3x^2+6x-72=0 are x=4,x=-6
Find the zeros of 3x^2+6x-72=0
The zeros of 3x^2+6x-72=0 are x=4,x=-6