What is ((2x-3))/((x+1))<= 1 ?

The solution to ((2x-3))/((x+1))<= 1 is -1<x<= 4

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((2x-3))/((x+1))<= 1

\frac{( 2 x - 3 )}{( x + 1 )} \leq 1

- 1 < x \leq 4

Interval Notation

(- 1, 4]

Solution steps

\frac{2 x - 3}{x + 1} \leq 1

Rewrite in standard form

\frac{x - 4}{x + 1} \leq 0

Identify the intervals

- 1 < x \leq 4

- \frac{3}{4} + \frac{7}{2} = - 43 + 27

(- 1)^{0}

3 hk - 2 k - 12 h + 8

\frac{x - 4}{2} - \frac{3 x + 1}{4} \leq \frac{- x}{8}

x^{2} - 4 \leq 2 x + 4