What are the solutions to the equation (x+6)+(x+4)=x^2+114 ?

The solutions to the equation (x+6)+(x+4)=x^2+114 are x=1+sqrt(103)i,x=1-sqrt(103)i

Find the zeros of (x+6)+(x+4)=x^2+114

The zeros of (x+6)+(x+4)=x^2+114 are x=1+sqrt(103)i,x=1-sqrt(103)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 6) + (x + 4) = x^{2} + 114

x = 1 + 103 i, x = 1 - 103 i

Solution steps

(x + 6) + (x + 4) = x^{2} + 114

Refine

2 x + 10 = x^{2} + 114

Switch sides

x^{2} + 114 = 2 x + 10

Move

10

to the left side

x^{2} + 104 = 2 x

Move

2 x

to the left side

x^{2} + 104 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x + 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 104}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 104 : 2103 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 103 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 103 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 103 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 103 i}{2 \cdot 1} : 1 + 103 i

x = \frac{- ( - 2 ) - 2 103 i}{2 \cdot 1} : 1 - 103 i

The solutions to the quadratic equation are:

x = 1 + 103 i, x = 1 - 103 i

3 x + 4 = - 8

64 c^{2} - 25

(b^{- \frac{1}{9}})^{2}

55 x^{6} + 22 x^{4}

\frac{x ^{4}}{x ^{7}}

What are the solutions to the equation (x+6)+(x+4)=x^2+114 ?
The solutions to the equation (x+6)+(x+4)=x^2+114 are x=1+sqrt(103)i,x=1-sqrt(103)i
Find the zeros of (x+6)+(x+4)=x^2+114
The zeros of (x+6)+(x+4)=x^2+114 are x=1+sqrt(103)i,x=1-sqrt(103)i