What are the solutions to the equation x^2-7x+3=0 ?

The solutions to the equation x^2-7x+3=0 are x=(7+sqrt(37))/2 ,x=(7-sqrt(37))/2

Find the zeros of x^2-7x+3=0

The zeros of x^2-7x+3=0 are x=(7+sqrt(37))/2 ,x=(7-sqrt(37))/2

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x^{2} - 7 x + 3 = 0

x = \frac{7 + 37}{2}, x = \frac{7 - 37}{2}

Decimal Notation

x = 6.54138 \dots, x = 0.45861 \dots

Solution steps

x^{2} - 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 3 = 37

x_{1, 2} = \frac{- ( - 7 ) \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 37}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 37}{2 \cdot 1}

x = \frac{- ( - 7 ) + 37}{2 \cdot 1} : \frac{7 + 37}{2}

x = \frac{- ( - 7 ) - 37}{2 \cdot 1} : \frac{7 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 37}{2}, x = \frac{7 - 37}{2}

f (a) = \frac{4 a ^{2} - 36 a}{2 a ^{4} - 24 a ^{3} + 54 a ^{2}}

\frac{h}{2} - \frac{5}{6} < \frac{7}{8} + h

4 x - 1 \leq - 37

2 x^{2} z + 10 x z + 8 z

- 2 x^{2} - 5 = - 2 x

What are the solutions to the equation x^2-7x+3=0 ?
The solutions to the equation x^2-7x+3=0 are x=(7+sqrt(37))/2 ,x=(7-sqrt(37))/2
Find the zeros of x^2-7x+3=0
The zeros of x^2-7x+3=0 are x=(7+sqrt(37))/2 ,x=(7-sqrt(37))/2