What are the solutions to the equation -2x^2-5=-2x ?

The solutions to the equation -2x^2-5=-2x are x= 1/2-i 3/2 ,x= 1/2+i 3/2

Find the zeros of -2x^2-5=-2x

The zeros of -2x^2-5=-2x are x= 1/2-i 3/2 ,x= 1/2+i 3/2

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- 2 x^{2} - 5 = - 2 x

x = \frac{1}{2} - i \frac{3}{2}, x = \frac{1}{2} + i \frac{3}{2}

Solution steps

- 2 x^{2} - 5 = - 2 x

Move

2 x

to the left side

- 2 x^{2} - 5 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

Simplify

2^{2} - 4 (- 2) (- 5) : 6 i

x_{1, 2} = \frac{- 2 \pm 6 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 2 + 6 i}{2 ( - 2 )}, x_{2} = \frac{- 2 - 6 i}{2 ( - 2 )}

x = \frac{- 2 + 6 i}{2 ( - 2 )} : \frac{1}{2} - i \frac{3}{2}

x = \frac{- 2 - 6 i}{2 ( - 2 )} : \frac{1}{2} + i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{3}{2}, x = \frac{1}{2} + i \frac{3}{2}

t^{2} - 15 = - 2 t

3 x^{2} + 18 x = 21

x^{2} - 6 x + 19 = 0

2 (x + 5) = - 8

\frac{8 !}{3 ! 5 !}

What are the solutions to the equation -2x^2-5=-2x ?
The solutions to the equation -2x^2-5=-2x are x= 1/2-i 3/2 ,x= 1/2+i 3/2
Find the zeros of -2x^2-5=-2x
The zeros of -2x^2-5=-2x are x= 1/2-i 3/2 ,x= 1/2+i 3/2