What are the solutions to the equation -2x^2+5x+3=0 ?

The solutions to the equation -2x^2+5x+3=0 are x=-1/2 ,x=3

Find the zeros of -2x^2+5x+3=0

The zeros of -2x^2+5x+3=0 are x=-1/2 ,x=3

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- 2 x^{2} + 5 x + 3 = 0

x = - \frac{1}{2}, x = 3

Solution steps

- 2 x^{2} + 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

5^{2} - 4 (- 2) \cdot 3 = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 ( - 2 )}, x_{2} = \frac{- 5 - 7}{2 ( - 2 )}

x = \frac{- 5 + 7}{2 ( - 2 )} : - \frac{1}{2}

x = \frac{- 5 - 7}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 3

4 (x + 6) + 3 \geq 9 + 5 x

∣ x - 5 ∣ > 4

- y^{2} - 12 y - 20

- x^{2} - 4 x + 36 = 0

2 x \cdot x^{\frac{1}{2}}

What are the solutions to the equation -2x^2+5x+3=0 ?
The solutions to the equation -2x^2+5x+3=0 are x=-1/2 ,x=3
Find the zeros of -2x^2+5x+3=0
The zeros of -2x^2+5x+3=0 are x=-1/2 ,x=3