What are the solutions to the equation (3k+4)^2=25 ?

The solutions to the equation (3k+4)^2=25 are k= 1/3 ,k=-3

Find the zeros of (3k+4)^2=25

The zeros of (3k+4)^2=25 are k= 1/3 ,k=-3

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(3 k + 4)^{2} = 25

k = \frac{1}{3}, k = - 3

Decimal Notation

k = 0.33333 \dots, k = - 3

Solution steps

(3 k + 4)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 k + 4 = 25 : k = \frac{1}{3}

Solve

3 k + 4 = - 25 : k = - 3

The solutions to the quadratic equation are:

k = \frac{1}{3}, k = - 3

\frac{( - 3 b ^{4} ) ^{2}}{- 12 b ^{- 9}}

v^{2} - 9 = 0

5 x^{2} + 1 = 4 x

s^{2} + 3 s - 40

32 + 4

What are the solutions to the equation (3k+4)^2=25 ?
The solutions to the equation (3k+4)^2=25 are k= 1/3 ,k=-3
Find the zeros of (3k+4)^2=25
The zeros of (3k+4)^2=25 are k= 1/3 ,k=-3