What is factor (a-b+1)^2-(1-a-b)^2 ?

The solution to factor (a-b+1)^2-(1-a-b)^2 is 4a(-b+1)

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factor (a-b+1)^2-(1-a-b)^2

factor

(a - b + 1)^{2} - (1 - a - b)^{2}

4 a (- b + 1)

Solution steps

(a - b + 1)^{2} - (1 - a - b)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a - b + 1)^{2} - (1 - a - b)^{2} = ((a - b + 1) + (1 - a - b)) ((a - b + 1) - (1 - a - b))

= ((a - b + 1) + (1 - a - b)) ((a - b + 1) - (1 - a - b))

Simplify

((a - b + 1) + (1 - a - b)) ((a - b + 1) - (1 - a - b)) : (- 2 b + 2) \cdot 2 a

= (- 2 b + 2) \cdot 2 a

= 2 a (- 2 b + 2)

Factor

- 2 b + 2 : 2 (- b + 1)

= 2 a \cdot 2 (- b + 1)

Multiply the numbers:

2 \cdot 2 = 4

= 4 a (- b + 1)

\frac{1}{\frac{π}{2} - ( - \frac{π}{2} )}

18 x^{2} - 9 x - 1 = 0

20 a^{4} b - 20 a^{3} b + 5 a^{2} b

(\frac{2}{2})^{3}

5 x^{2} + 3 x + 2 = 0

What is factor (a-b+1)^2-(1-a-b)^2 ?
The solution to factor (a-b+1)^2-(1-a-b)^2 is 4a(-b+1)