What is factor w^2+w-12 ?

The solution to factor w^2+w-12 is (w-3)(w+4)

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factor w^2+w-12

factor

w^{2} + w - 12

(w - 3) (w + 4)

Solution steps

w^{2} + w - 12

Break the expression into groups

= (w^{2} - 3 w) + (4 w - 12)

Factor out

w

from

w^{2} - 3 w : w (w - 3)

Factor out

4

from

4 w - 12 : 4 (w - 3)

= w (w - 3) + 4 (w - 3)

Factor out common term

w - 3

= (w - 3) (w + 4)

\frac{4}{5} x - 8 = 12

(2 x - 7)^{2} + 8 = 0

x^{2} - 12 x + 27 < 0

(\frac{1}{6})^{\frac{1}{6}}

\frac{2}{3 + i}