What are the solutions to the equation 6x^2+17=11 ?

The solutions to the equation 6x^2+17=11 are x=i,x=-i

Find the zeros of 6x^2+17=11

The zeros of 6x^2+17=11 are x=i,x=-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 17 = 11

x = i, x = - i

Solution steps

6 x^{2} + 17 = 11

Move

17

to the right side

6 x^{2} = - 6

Divide both sides by

6

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

\frac{1}{x + 1} + \frac{1}{x + 2} \leq 0

x - 1 = 2 x

2^{3} \cdot 2^{5}

\frac{t}{t ^{2}}

(2 + 3)^{2}

What are the solutions to the equation 6x^2+17=11 ?
The solutions to the equation 6x^2+17=11 are x=i,x=-i
Find the zeros of 6x^2+17=11
The zeros of 6x^2+17=11 are x=i,x=-i