What are the solutions to the equation y^2-10y=-23 ?

The solutions to the equation y^2-10y=-23 are y=5+sqrt(2),y=5-sqrt(2)

Find the zeros of y^2-10y=-23

The zeros of y^2-10y=-23 are y=5+sqrt(2),y=5-sqrt(2)

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y^{2} - 10 y = - 23

y = 5 + 2, y = 5 - 2

Decimal Notation

y = 6.41421 \dots, y = 3.58578 \dots

Solution steps

y^{2} - 10 y = - 23

Move

23

to the left side

y^{2} - 10 y + 23 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 23 = 22

y_{1, 2} = \frac{- ( - 10 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 2 2}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 2 2}{2 \cdot 1}

y = \frac{- ( - 10 ) + 2 2}{2 \cdot 1} : 5 + 2

y = \frac{- ( - 10 ) - 2 2}{2 \cdot 1} : 5 - 2

The solutions to the quadratic equation are:

y = 5 + 2, y = 5 - 2

- 2 (x + 2) > 10

- 3 x + 7 \leq 19

\frac{x ^{2} y - 3 x y ^{2} + 6 x ^{2} y + x y}{x y}

4 n (3 n^{2} + n - 4) - n (3 - n)

\frac{c + 2}{c - 5} - \frac{c}{c + 1}

What are the solutions to the equation y^2-10y=-23 ?
The solutions to the equation y^2-10y=-23 are y=5+sqrt(2),y=5-sqrt(2)
Find the zeros of y^2-10y=-23
The zeros of y^2-10y=-23 are y=5+sqrt(2),y=5-sqrt(2)