What are the solutions to the equation x^2-5x+14=0 ?

The solutions to the equation x^2-5x+14=0 are x= 5/2+i(sqrt(31))/2 ,x= 5/2-i(sqrt(31))/2

Find the zeros of x^2-5x+14=0

The zeros of x^2-5x+14=0 are x= 5/2+i(sqrt(31))/2 ,x= 5/2-i(sqrt(31))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 5 x + 14 = 0

x = \frac{5}{2} + i \frac{31}{2}, x = \frac{5}{2} - i \frac{31}{2}

Solution steps

x^{2} - 5 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 14 : 31 i

x_{1, 2} = \frac{- ( - 5 ) \pm 31 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 31 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 31 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 31 i}{2 \cdot 1} : \frac{5}{2} + i \frac{31}{2}

x = \frac{- ( - 5 ) - 31 i}{2 \cdot 1} : \frac{5}{2} - i \frac{31}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{31}{2}, x = \frac{5}{2} - i \frac{31}{2}

10 r^{2} + 7 = - 113

(x^{3}) (4 x^{5})

4 X = 10

0.73 (7)^{2} + 15.8 (7) + 2.7

What are the solutions to the equation x^2-5x+14=0 ?
The solutions to the equation x^2-5x+14=0 are x= 5/2+i(sqrt(31))/2 ,x= 5/2-i(sqrt(31))/2
Find the zeros of x^2-5x+14=0
The zeros of x^2-5x+14=0 are x= 5/2+i(sqrt(31))/2 ,x= 5/2-i(sqrt(31))/2