What are the solutions to the equation 6x^2-2x+36=5x^2+10x ?

The solutions to the equation 6x^2-2x+36=5x^2+10x are x=6

Find the zeros of 6x^2-2x+36=5x^2+10x

The zeros of 6x^2-2x+36=5x^2+10x are x=6

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6 x^{2} - 2 x + 36 = 5 x^{2} + 10 x

x = 6

Solution steps

6 x^{2} - 2 x + 36 = 5 x^{2} + 10 x

Move

10 x

to the left side

6 x^{2} - 12 x + 36 = 5 x^{2}

Move

5 x^{2}

to the left side

x^{2} - 12 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 36 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 12 )}{2 \cdot 1}

\frac{- ( - 12 )}{2 \cdot 1} = 6

x = 6

The solution to the quadratic equation is:

x = 6

8 + \frac{1}{2}

∣ 3 b + 11 ∣ = 1

∣ 2 x + 1 ∣ < 9

6 x - 4 > - 34

2 (4 x - 1)^{2} + (4 x - 1) \geq 0

What are the solutions to the equation 6x^2-2x+36=5x^2+10x ?
The solutions to the equation 6x^2-2x+36=5x^2+10x are x=6
Find the zeros of 6x^2-2x+36=5x^2+10x
The zeros of 6x^2-2x+36=5x^2+10x are x=6