What are the solutions to the equation 0=-x^2+4x+2 ?

The solutions to the equation 0=-x^2+4x+2 are x=2-sqrt(6),x=2+sqrt(6)

Find the zeros of 0=-x^2+4x+2

The zeros of 0=-x^2+4x+2 are x=2-sqrt(6),x=2+sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - x^{2} + 4 x + 2

x = 2 - 6, x = 2 + 6

Decimal Notation

x = - 0.44948 \dots, x = 4.44948 \dots

Solution steps

0 = - x^{2} + 4 x + 2

Switch sides

- x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 2 = 26

x_{1, 2} = \frac{- 4 \pm 2 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 6}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 6}{2 ( - 1 )}

x = \frac{- 4 + 2 6}{2 ( - 1 )} : 2 - 6

x = \frac{- 4 - 2 6}{2 ( - 1 )} : 2 + 6

The solutions to the quadratic equation are:

x = 2 - 6, x = 2 + 6

\frac{( x ^{2} + y ^{2} ) ^{\frac{1}{4}} + 4 ( x ^{2} + y ^{2} ) ^{- \frac{3}{4}}}{x ^{2} + y ^{2}}

- 40 > - 10 k

\frac{3 x + 8}{7} = \frac{- 3 x + 12}{3}

\frac{2}{5} (9 x + 5) = 5 - x

x^{2} + 32 x + 260 = 0

What are the solutions to the equation 0=-x^2+4x+2 ?
The solutions to the equation 0=-x^2+4x+2 are x=2-sqrt(6),x=2+sqrt(6)
Find the zeros of 0=-x^2+4x+2
The zeros of 0=-x^2+4x+2 are x=2-sqrt(6),x=2+sqrt(6)