What is ((x^2+y^2)^{1/4}+4(x^2+y^2)^{-3/4})/(x^2+y^2) ?

The solution to ((x^2+y^2)^{1/4}+4(x^2+y^2)^{-3/4})/(x^2+y^2) is (x^2+y^2+4)/((x^2+y^2)^{7/4)}

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simplify ((x^2+y^2)^{1/4}+4(x^2+y^2)^{-3/4})/(x^2+y^2)

simplify

\frac{( x ^{2} + y ^{2} ) ^{\frac{1}{4}} + 4 ( x ^{2} + y ^{2} ) ^{- \frac{3}{4}}}{x ^{2} + y ^{2}}

\frac{x ^{2} + y ^{2} + 4}{( x ^{2} + y ^{2} ) ^{\frac{7}{4}}}

Solution steps

\frac{( x ^{2} + y ^{2} ) ^{\frac{1}{4}} + 4 ( x ^{2} + y ^{2} ) ^{- \frac{3}{4}}}{x ^{2} + y ^{2}}

Simplify

(x^{2} + y^{2})^{\frac{1}{4}} + 4 (x^{2} + y^{2})^{- \frac{3}{4}} : \frac{x ^{2} + y ^{2} + 4}{( x ^{2} + y ^{2} ) ^{\frac{3}{4}}}

= \frac{\frac{x ^{2} + y ^{2} + 4}{( x ^{2} + y ^{2} ) ^{\frac{3}{4}}}}{x ^{2} + y ^{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{x ^{2} + y ^{2} + 4}{( x ^{2} + y ^{2} ) ^{\frac{3}{4}} ( x ^{2} + y ^{2} )}

Simplify

(x^{2} + y^{2})^{\frac{3}{4}} (x^{2} + y^{2}) : (x^{2} + y^{2})^{\frac{7}{4}}

= \frac{x ^{2} + y ^{2} + 4}{( x ^{2} + y ^{2} ) ^{\frac{7}{4}}}

- 40 > - 10 k

\frac{3 x + 8}{7} = \frac{- 3 x + 12}{3}

\frac{2}{5} (9 x + 5) = 5 - x

x^{2} + 32 x + 260 = 0

(g - 11) (g - 5) = 35

What is ((x^2+y^2)^{1/4}+4(x^2+y^2)^{-3/4})/(x^2+y^2) ?
The solution to ((x^2+y^2)^{1/4}+4(x^2+y^2)^{-3/4})/(x^2+y^2) is (x^2+y^2+4)/((x^2+y^2)^{7/4)}