What are the solutions to the equation 1-x-x^2=0 ?

The solutions to the equation 1-x-x^2=0 are x=-(1+sqrt(5))/2 ,x=(sqrt(5)-1)/2

Find the zeros of 1-x-x^2=0

The zeros of 1-x-x^2=0 are x=-(1+sqrt(5))/2 ,x=(sqrt(5)-1)/2

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1 - x - x^{2} = 0

x = - \frac{1 + 5}{2}, x = \frac{5 - 1}{2}

Decimal Notation

x = - 1.61803 \dots, x = 0.61803 \dots

Solution steps

1 - x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 1 = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 5}{2 ( - 1 )} : - \frac{1 + 5}{2}

x = \frac{- ( - 1 ) - 5}{2 ( - 1 )} : \frac{5 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 5}{2}, x = \frac{5 - 1}{2}

(\frac{1}{2} \cdot (\frac{2}{7})^{- 3})^{2}

0 = - 16 t^{2} + 80 t

5 x^{2} - 20 x

14 x^{2} - 17 x - 6

- 6 + 9 (8 - 2 b)

What are the solutions to the equation 1-x-x^2=0 ?
The solutions to the equation 1-x-x^2=0 are x=-(1+sqrt(5))/2 ,x=(sqrt(5)-1)/2
Find the zeros of 1-x-x^2=0
The zeros of 1-x-x^2=0 are x=-(1+sqrt(5))/2 ,x=(sqrt(5)-1)/2