What are the solutions to the equation -24x^2-7=11x ?

The solutions to the equation -24x^2-7=11x are x=-11/48-i(sqrt(551))/(48),x=-11/48+i(sqrt(551))/(48)

Find the zeros of -24x^2-7=11x

The zeros of -24x^2-7=11x are x=-11/48-i(sqrt(551))/(48),x=-11/48+i(sqrt(551))/(48)

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- 24 x^{2} - 7 = 11 x

x = - \frac{11}{48} - i \frac{551}{48}, x = - \frac{11}{48} + i \frac{551}{48}

Solution steps

- 24 x^{2} - 7 = 11 x

Move

11 x

to the left side

- 24 x^{2} - 7 - 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 24 x^{2} - 11 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 ( - 24 ) ( - 7 )}{2 ( - 24 )}

Simplify

(- 11)^{2} - 4 (- 24) (- 7) : 551 i

x_{1, 2} = \frac{- ( - 11 ) \pm 551 i}{2 ( - 24 )}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 551 i}{2 ( - 24 )}, x_{2} = \frac{- ( - 11 ) - 551 i}{2 ( - 24 )}

x = \frac{- ( - 11 ) + 551 i}{2 ( - 24 )} : - \frac{11}{48} - i \frac{551}{48}

x = \frac{- ( - 11 ) - 551 i}{2 ( - 24 )} : - \frac{11}{48} + i \frac{551}{48}

The solutions to the quadratic equation are:

x = - \frac{11}{48} - i \frac{551}{48}, x = - \frac{11}{48} + i \frac{551}{48}

6 z^{2} - 7 z - 3 = 0

3 a + 9 = 54

(3 + 2)^{2} \cdot 2

\frac{x}{x - 4} > 5

\frac{x}{7} - \frac{x}{9} = 2

What are the solutions to the equation -24x^2-7=11x ?
The solutions to the equation -24x^2-7=11x are x=-11/48-i(sqrt(551))/(48),x=-11/48+i(sqrt(551))/(48)
Find the zeros of -24x^2-7=11x
The zeros of -24x^2-7=11x are x=-11/48-i(sqrt(551))/(48),x=-11/48+i(sqrt(551))/(48)