What are the solutions to the equation w^2-8w+3=0 ?

The solutions to the equation w^2-8w+3=0 are w=4+sqrt(13),w=4-sqrt(13)

Find the zeros of w^2-8w+3=0

The zeros of w^2-8w+3=0 are w=4+sqrt(13),w=4-sqrt(13)

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w^{2} - 8 w + 3 = 0

w = 4 + 13, w = 4 - 13

Decimal Notation

w = 7.60555 \dots, w = 0.39444 \dots

Solution steps

w^{2} - 8 w + 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 3 = 213

w_{1, 2} = \frac{- ( - 8 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 8 ) + 2 13}{2 \cdot 1}, w_{2} = \frac{- ( - 8 ) - 2 13}{2 \cdot 1}

w = \frac{- ( - 8 ) + 2 13}{2 \cdot 1} : 4 + 13

w = \frac{- ( - 8 ) - 2 13}{2 \cdot 1} : 4 - 13

The solutions to the quadratic equation are:

w = 4 + 13, w = 4 - 13

x^{4} + 3 x^{3} - x^{2} - 3 x

2 x + 8 = 4

6^{2} + 24 (2) \leq \frac{( 5 x + 4 x )}{2}

- \frac{10}{- 6}

18 x^{3} y^{2}

What are the solutions to the equation w^2-8w+3=0 ?
The solutions to the equation w^2-8w+3=0 are w=4+sqrt(13),w=4-sqrt(13)
Find the zeros of w^2-8w+3=0
The zeros of w^2-8w+3=0 are w=4+sqrt(13),w=4-sqrt(13)