What are the solutions to the equation x^2+8x-16=0 ?

The solutions to the equation x^2+8x-16=0 are x=4(sqrt(2)-1),x=-4(1+sqrt(2))

Find the zeros of x^2+8x-16=0

The zeros of x^2+8x-16=0 are x=4(sqrt(2)-1),x=-4(1+sqrt(2))

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x^{2} + 8 x - 16 = 0

x = 4 (2 - 1), x = - 4 (1 + 2)

Decimal Notation

x = 1.65685 \dots, x = - 9.65685 \dots

Solution steps

x^{2} + 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 16) = 82

x_{1, 2} = \frac{- 8 \pm 8 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8 2}{2 \cdot 1}, x_{2} = \frac{- 8 - 8 2}{2 \cdot 1}

x = \frac{- 8 + 8 2}{2 \cdot 1} : 4 (2 - 1)

x = \frac{- 8 - 8 2}{2 \cdot 1} : - 4 (1 + 2)

The solutions to the quadratic equation are:

x = 4 (2 - 1), x = - 4 (1 + 2)

5 x^{2} - 3 x - 2

8 = 2 x

2 x^{2} + 6 x + 1 = 0

\frac{y ^{4} + 5 y ^{2} + 6}{4 y ^{5} + 12 y ^{3}}

x^{4} + 3 x^{3} - x^{2} + x + 4

What are the solutions to the equation x^2+8x-16=0 ?
The solutions to the equation x^2+8x-16=0 are x=4(sqrt(2)-1),x=-4(1+sqrt(2))
Find the zeros of x^2+8x-16=0
The zeros of x^2+8x-16=0 are x=4(sqrt(2)-1),x=-4(1+sqrt(2))