What are the solutions to the equation 2x^2-6x-8=0 ?

The solutions to the equation 2x^2-6x-8=0 are x=4,x=-1

Find the zeros of 2x^2-6x-8=0

The zeros of 2x^2-6x-8=0 are x=4,x=-1

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2 x^{2} - 6 x - 8 = 0

x = 4, x = - 1

Solution steps

2 x^{2} - 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 8) = 10

x_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 2}

x = \frac{- ( - 6 ) + 10}{2 \cdot 2} : 4

x = \frac{- ( - 6 ) - 10}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

∣ 2 x - 3 ∣ \leq 9

- 2 (3 x - 3) = 3 x

\frac{x y + 3 x - y - 3}{x y - 2 x + 4 y - 8}

\frac{u}{4} = 72

\frac{3 ^{- 1} + 6 ^{- 1}}{8 ^{- 1}}

What are the solutions to the equation 2x^2-6x-8=0 ?
The solutions to the equation 2x^2-6x-8=0 are x=4,x=-1
Find the zeros of 2x^2-6x-8=0
The zeros of 2x^2-6x-8=0 are x=4,x=-1