What are the solutions to the equation 3.2x^2+7x-21=0 ?

The solutions to the equation 3.2x^2+7x-21=0 are x=(-35+sqrt(7945))/(32),x=-(35+sqrt(7945))/(32)

Find the zeros of 3.2x^2+7x-21=0

The zeros of 3.2x^2+7x-21=0 are x=(-35+sqrt(7945))/(32),x=-(35+sqrt(7945))/(32)

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3.2 x^{2} + 7 x - 21 = 0

x = \frac{- 35 + 7945}{32}, x = - \frac{35 + 7945}{32}

Solution steps

3.2 x^{2} + 7 x - 21 = 0

Multiply both sides by

10

32 x^{2} + 70 x - 210 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 \cdot 32 ( - 210 )}{2 \cdot 32}

7 0^{2} - 4 \cdot 32 (- 210) = 27945

x_{1, 2} = \frac{- 70 \pm 2 7945}{2 \cdot 32}

Separate the solutions

x_{1} = \frac{- 70 + 2 7945}{2 \cdot 32}, x_{2} = \frac{- 70 - 2 7945}{2 \cdot 32}

x = \frac{- 70 + 2 7945}{2 \cdot 32} : \frac{- 35 + 7945}{32}

x = \frac{- 70 - 2 7945}{2 \cdot 32} : - \frac{35 + 7945}{32}

The solutions to the quadratic equation are:

x = \frac{- 35 + 7945}{32}, x = - \frac{35 + 7945}{32}

\frac{5 a ^{2} - 46 a + 9}{a - 9}

x^{2} - 0.3 x - 0.04 = 0

- 0.2 x^{2} - 1 0^{- 4.7} x + 1 0^{- 4.7} = 0

- 6 + 9 ∣ x + 3 ∣ = 12

10 \cdot 6^{x} \leq 2 \cdot 6^{- x} - 8

What are the solutions to the equation 3.2x^2+7x-21=0 ?
The solutions to the equation 3.2x^2+7x-21=0 are x=(-35+sqrt(7945))/(32),x=-(35+sqrt(7945))/(32)
Find the zeros of 3.2x^2+7x-21=0
The zeros of 3.2x^2+7x-21=0 are x=(-35+sqrt(7945))/(32),x=-(35+sqrt(7945))/(32)