What is the answer to 3(u+3)+u=2(u-1)+3 ?

The answer to 3(u+3)+u=2(u-1)+3 is u=-4

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3(u+3)+u=2(u-1)+3

3 (u + 3) + u = 2 (u - 1) + 3

u = - 4

Solution steps

3 (u + 3) + u = 2 (u - 1) + 3

Expand

3 (u + 3) + u : 4 u + 9

Expand

2 (u - 1) + 3 : 2 u + 1

4 u + 9 = 2 u + 1

Move

9

to the right side

4 u = 2 u - 8

Move

2 u

to the left side

2 u = - 8

Divide both sides by

2

u = - 4

(\frac{1}{x} + \frac{1}{x} + \frac{1}{x})^{- 1}

9 x^{2} - 3 x y + 6 x - 2 y

x^{2} - 12 x + 31 = 0

2 y + (- 23) = - 10 - (- 39)

u^{2} = 16 u + 36

What is the answer to 3(u+3)+u=2(u-1)+3 ?
The answer to 3(u+3)+u=2(u-1)+3 is u=-4
Solve for u: 3(u+3)+u=2(u-1)+3
The solution is u=-4