What are the solutions to the equation 6r^2+3r-3=0 ?

The solutions to the equation 6r^2+3r-3=0 are r= 1/2 ,r=-1

Find the zeros of 6r^2+3r-3=0

The zeros of 6r^2+3r-3=0 are r= 1/2 ,r=-1

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6 r^{2} + 3 r - 3 = 0

r = \frac{1}{2}, r = - 1

Solution steps

6 r^{2} + 3 r - 3 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

3^{2} - 4 \cdot 6 (- 3) = 9

r_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 6}

Separate the solutions

r_{1} = \frac{- 3 + 9}{2 \cdot 6}, r_{2} = \frac{- 3 - 9}{2 \cdot 6}

r = \frac{- 3 + 9}{2 \cdot 6} : \frac{1}{2}

r = \frac{- 3 - 9}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

r = \frac{1}{2}, r = - 1

6 (4)^{2}

9.8 (0.35)

n^{2} + 5 n - 6 = 0

- 16 = - 16

9 n + 16 \leq 22 + 7 n

What are the solutions to the equation 6r^2+3r-3=0 ?
The solutions to the equation 6r^2+3r-3=0 are r= 1/2 ,r=-1
Find the zeros of 6r^2+3r-3=0
The zeros of 6r^2+3r-3=0 are r= 1/2 ,r=-1