What are the solutions to the equation 3x^2-3x=0 ?

The solutions to the equation 3x^2-3x=0 are x=1,x=0

Find the zeros of 3x^2-3x=0

The zeros of 3x^2-3x=0 are x=1,x=0

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3 x^{2} - 3 x = 0

x = 1, x = 0

Solution steps

3 x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 3}

x = \frac{- ( - 3 ) + 3}{2 \cdot 3} : 1

x = \frac{- ( - 3 ) - 3}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

7 x^{2} - 5 x - 9 = 0

1 - (- 3)

b^{2} + 12 b + 35 = 0

x^{2} - 10 x - 100 = 0

\frac{1}{49}

What are the solutions to the equation 3x^2-3x=0 ?
The solutions to the equation 3x^2-3x=0 are x=1,x=0
Find the zeros of 3x^2-3x=0
The zeros of 3x^2-3x=0 are x=1,x=0