What are the solutions to the equation b^2+12b+35=0 ?

The solutions to the equation b^2+12b+35=0 are b=-5,b=-7

Find the zeros of b^2+12b+35=0

The zeros of b^2+12b+35=0 are b=-5,b=-7

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b^{2} + 12 b + 35 = 0

b = - 5, b = - 7

Solution steps

b^{2} + 12 b + 35 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 35 = 2

b_{1, 2} = \frac{- 12 \pm 2}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- 12 + 2}{2 \cdot 1}, b_{2} = \frac{- 12 - 2}{2 \cdot 1}

b = \frac{- 12 + 2}{2 \cdot 1} : - 5

b = \frac{- 12 - 2}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

b = - 5, b = - 7

(\frac{27}{64})^{\frac{2}{3}}

x^{2} - 10 x - 100 = 0

\frac{1}{49}

t = \frac{2328}{388}

x^{2} = 4 x - 40

What are the solutions to the equation b^2+12b+35=0 ?
The solutions to the equation b^2+12b+35=0 are b=-5,b=-7
Find the zeros of b^2+12b+35=0
The zeros of b^2+12b+35=0 are b=-5,b=-7