What are the solutions to the equation 20x^2+7x-3=0 ?

The solutions to the equation 20x^2+7x-3=0 are x= 1/4 ,x=-3/5

Find the zeros of 20x^2+7x-3=0

The zeros of 20x^2+7x-3=0 are x= 1/4 ,x=-3/5

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20 x^{2} + 7 x - 3 = 0

x = \frac{1}{4}, x = - \frac{3}{5}

Solution steps

20 x^{2} + 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 20 ( - 3 )}{2 \cdot 20}

7^{2} - 4 \cdot 20 (- 3) = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 \cdot 20}, x_{2} = \frac{- 7 - 17}{2 \cdot 20}

x = \frac{- 7 + 17}{2 \cdot 20} : \frac{1}{4}

x = \frac{- 7 - 17}{2 \cdot 20} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{3}{5}

12 x^{2} + x - 6 = 0

9 (2 m - 3)^{2} + 8 = 449

(3 + 2 i) (3 - 2 i)

\frac{x + 1}{2} = \frac{x}{7}

6 x y - 3 x - 8 y + 4

What are the solutions to the equation 20x^2+7x-3=0 ?
The solutions to the equation 20x^2+7x-3=0 are x= 1/4 ,x=-3/5
Find the zeros of 20x^2+7x-3=0
The zeros of 20x^2+7x-3=0 are x= 1/4 ,x=-3/5