What are the solutions to the equation x^2=4x-40 ?

The solutions to the equation x^2=4x-40 are x=2+6i,x=2-6i

Find the zeros of x^2=4x-40

The zeros of x^2=4x-40 are x=2+6i,x=2-6i

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x^{2} = 4 x - 40

x = 2 + 6 i, x = 2 - 6 i

Solution steps

x^{2} = 4 x - 40

Move

40

to the left side

x^{2} + 40 = 4 x

Move

4 x

to the left side

x^{2} + 40 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 40 : 12 i

x_{1, 2} = \frac{- ( - 4 ) \pm 12 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 12 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 12 i}{2 \cdot 1} : 2 + 6 i

x = \frac{- ( - 4 ) - 12 i}{2 \cdot 1} : 2 - 6 i

The solutions to the quadratic equation are:

x = 2 + 6 i, x = 2 - 6 i

\frac{1}{2} x + \frac{3}{2} x + 6 x - 3 x

- 2 ∣ 5 x + 6 ∣ + 1 \leq - 27

- 7 x^{2} + 14 x + 21 = 0

g^{2} + 11 g + 24

\frac{a}{a ^{2} - 4} - \frac{1}{a - 2}

What are the solutions to the equation x^2=4x-40 ?
The solutions to the equation x^2=4x-40 are x=2+6i,x=2-6i
Find the zeros of x^2=4x-40
The zeros of x^2=4x-40 are x=2+6i,x=2-6i