What are the solutions to the equation 4x^2+6x-5=0 ?

The solutions to the equation 4x^2+6x-5=0 are x=(-3+sqrt(29))/4 ,x=-(3+sqrt(29))/4

Find the zeros of 4x^2+6x-5=0

The zeros of 4x^2+6x-5=0 are x=(-3+sqrt(29))/4 ,x=-(3+sqrt(29))/4

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4 x^{2} + 6 x - 5 = 0

x = \frac{- 3 + 29}{4}, x = - \frac{3 + 29}{4}

Decimal Notation

x = 0.59629 \dots, x = - 2.09629 \dots

Solution steps

4 x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 5) = 229

x_{1, 2} = \frac{- 6 \pm 2 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 2 29}{2 \cdot 4}, x_{2} = \frac{- 6 - 2 29}{2 \cdot 4}

x = \frac{- 6 + 2 29}{2 \cdot 4} : \frac{- 3 + 29}{4}

x = \frac{- 6 - 2 29}{2 \cdot 4} : - \frac{3 + 29}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 29}{4}, x = - \frac{3 + 29}{4}

(- 32)^{0.6}

14 x^{2} + 11 x - 3

4 x^{2} - 16 x + 11 = 0

343 x^{3} + y^{9}

(x + 2) (x - 3) > 2 - x

What are the solutions to the equation 4x^2+6x-5=0 ?
The solutions to the equation 4x^2+6x-5=0 are x=(-3+sqrt(29))/4 ,x=-(3+sqrt(29))/4
Find the zeros of 4x^2+6x-5=0
The zeros of 4x^2+6x-5=0 are x=(-3+sqrt(29))/4 ,x=-(3+sqrt(29))/4