What is ((-ab^2c)^{-1})/(a^{-2)bc^{-1}} ?

The solution to ((-ab^2c)^{-1})/(a^{-2)bc^{-1}} is -a/(b^3)

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simplify ((-ab^2c)^{-1})/(a^{-2)bc^{-1}}

simplify

\frac{( - a b ^{2} c ) ^{- 1}}{a ^{- 2} b c ^{- 1}}

- \frac{a}{b ^{3}}

Solution steps

\frac{( - a b ^{2} c ) ^{- 1}}{a ^{- 2} b c ^{- 1}}

Simplify

(- a b^{2} c)^{- 1} : - \frac{1}{a b ^{2} c}

= \frac{- \frac{1}{a b ^{2} c}}{a ^{- 2} b c ^{- 1}}

Simplify

a^{- 2} b c^{- 1} : \frac{b}{a ^{2} c}

= \frac{- \frac{1}{a b ^{2} c}}{\frac{b}{a ^{2} c}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{1}{a b ^{2} c}}{\frac{b}{a ^{2} c}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

\frac{\frac{1}{a b ^{2} c}}{\frac{b}{a ^{2} c}} = \frac{1 \cdot a ^{2} c}{a b ^{2} c b}

= - \frac{1 \cdot a ^{2} c}{a b ^{2} c b}

Cancel

- \frac{1 \cdot a ^{2} c}{a b ^{2} c b} : - \frac{a}{b ^{3}}

= - \frac{a}{b ^{3}}

x^{3} - 4 x^{2} - 4 x + 16

4 n + 2 = 6

11 (n - 1) + 35 = 3 n

9 x^{2} + 49 = 0

3 v = \frac{9}{5}

What is ((-ab^2c)^{-1})/(a^{-2)bc^{-1}} ?
The solution to ((-ab^2c)^{-1})/(a^{-2)bc^{-1}} is -a/(b^3)