What are the solutions to the equation x^2+2x=-2 ?

The solutions to the equation x^2+2x=-2 are x=-1+i,x=-1-i

Find the zeros of x^2+2x=-2

The zeros of x^2+2x=-2 are x=-1+i,x=-1-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 x = - 2

x = - 1 + i, x = - 1 - i

Solution steps

x^{2} + 2 x = - 2

Move

2

to the left side

x^{2} + 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

x_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

x = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

x = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

x = - 1 + i, x = - 1 - i

3 x^{2} - 2 = 5

5 (x + 1) = 35

∣ x + 1 ∣ \geq 7

- \frac{5}{2} x = 15

4 y - 5 + y = 10

What are the solutions to the equation x^2+2x=-2 ?
The solutions to the equation x^2+2x=-2 are x=-1+i,x=-1-i
Find the zeros of x^2+2x=-2
The zeros of x^2+2x=-2 are x=-1+i,x=-1-i