What are the solutions to the equation z^2+16=0 ?

The solutions to the equation z^2+16=0 are z=4i,z=-4i

Find the zeros of z^2+16=0

The zeros of z^2+16=0 are z=4i,z=-4i

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z^{2} + 16 = 0

z = 4 i, z = - 4 i

Solution steps

z^{2} + 16 = 0

Move

16

to the right side

z^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 16, z = - - 16

- 16 = 4 i

- - 16 = - 4 i

z = 4 i, z = - 4 i

\frac{x}{x + 4} \geq 2

125 b^{2} - 20 c^{4}

25 y^{2} + 40 y + 16

12 x^{2} + 4 x - 5

544

What are the solutions to the equation z^2+16=0 ?
The solutions to the equation z^2+16=0 are z=4i,z=-4i
Find the zeros of z^2+16=0
The zeros of z^2+16=0 are z=4i,z=-4i