What are the solutions to the equation x^2=289 ?

The solutions to the equation x^2=289 are x=17,x=-17

Find the zeros of x^2=289

The zeros of x^2=289 are x=17,x=-17

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x^{2} = 289

x = 17, x = - 17

Solution steps

x^{2} = 289

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 289, x = - 289

289 = 17

- 289 = - 17

x = 17, x = - 17

x^{2} - 3 x = 10

5 x^{2} + 12 x + 4 = 0

6 (2 x - 3) = 9 x - 18 + 3 x

(- 125) \frac{2}{3}

6 s^{2} = - 48

What are the solutions to the equation x^2=289 ?
The solutions to the equation x^2=289 are x=17,x=-17
Find the zeros of x^2=289
The zeros of x^2=289 are x=17,x=-17