What are the solutions to the equation w^2+3=19 ?

The solutions to the equation w^2+3=19 are w=4,w=-4

Find the zeros of w^2+3=19

The zeros of w^2+3=19 are w=4,w=-4

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w^{2} + 3 = 19

w = 4, w = - 4

Solution steps

w^{2} + 3 = 19

Move

3

to the right side

w^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = 16, w = - 16

16 = 4

- 16 = - 4

w = 4, w = - 4

y^{2} + 3 y + \frac{9}{4}

m^{2} + m + 2 = 0

(2 x + 4) \cdot (x - 1) + (3 x + 5)^{2} = 3 (2 x + 5)^{2} + x

\frac{5 !}{( 5 - 3 ) !}

- x - 8 \geq - 5

What are the solutions to the equation w^2+3=19 ?
The solutions to the equation w^2+3=19 are w=4,w=-4
Find the zeros of w^2+3=19
The zeros of w^2+3=19 are w=4,w=-4