What are the solutions to the equation 2k^2-5k+3=0 ?

The solutions to the equation 2k^2-5k+3=0 are k= 3/2 ,k=1

Find the zeros of 2k^2-5k+3=0

The zeros of 2k^2-5k+3=0 are k= 3/2 ,k=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 k^{2} - 5 k + 3 = 0

k = \frac{3}{2}, k = 1

Solution steps

2 k^{2} - 5 k + 3 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 3 = 1

k_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 2}, k_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 2}

k = \frac{- ( - 5 ) + 1}{2 \cdot 2} : \frac{3}{2}

k = \frac{- ( - 5 ) - 1}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

k = \frac{3}{2}, k = 1

39 = 5 x + 4

7 > 25 - 23

2 \geq s - 2

\frac{\frac{16 x ^{2} - y ^{2}}{x y}}{\frac{4}{y} - \frac{1}{x}}

i^{102}

What are the solutions to the equation 2k^2-5k+3=0 ?
The solutions to the equation 2k^2-5k+3=0 are k= 3/2 ,k=1
Find the zeros of 2k^2-5k+3=0
The zeros of 2k^2-5k+3=0 are k= 3/2 ,k=1