What are the solutions to the equation -5x-15=x^2+x-2 ?

The solutions to the equation -5x-15=x^2+x-2 are x=-3+2i,x=-3-2i

Find the zeros of -5x-15=x^2+x-2

The zeros of -5x-15=x^2+x-2 are x=-3+2i,x=-3-2i

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- 5 x - 15 = x^{2} + x - 2

x = - 3 + 2 i, x = - 3 - 2 i

Solution steps

- 5 x - 15 = x^{2} + x - 2

Switch sides

x^{2} + x - 2 = - 5 x - 15

Move

15

to the left side

x^{2} + x + 13 = - 5 x

Move

5 x

to the left side

x^{2} + 6 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 13 : 4 i

x_{1, 2} = \frac{- 6 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 i}{2 \cdot 1}

x = \frac{- 6 + 4 i}{2 \cdot 1} : - 3 + 2 i

x = \frac{- 6 - 4 i}{2 \cdot 1} : - 3 - 2 i

The solutions to the quadratic equation are:

x = - 3 + 2 i, x = - 3 - 2 i

\frac{16}{9} = - 8 x

3 x - \frac{3}{7} = \frac{7}{3}

\frac{75}{12}

2 x^{3} + 3 x^{2} - 32 x - 48

6 - 4 i

What are the solutions to the equation -5x-15=x^2+x-2 ?
The solutions to the equation -5x-15=x^2+x-2 are x=-3+2i,x=-3-2i
Find the zeros of -5x-15=x^2+x-2
The zeros of -5x-15=x^2+x-2 are x=-3+2i,x=-3-2i