What is factor 2x^3+3x^2-32x-48 ?

The solution to factor 2x^3+3x^2-32x-48 is (2x+3)(x+4)(x-4)

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factor 2x^3+3x^2-32x-48

factor

2 x^{3} + 3 x^{2} - 32 x - 48

(2 x + 3) (x + 4) (x - 4)

Solution steps

2 x^{3} + 3 x^{2} - 32 x - 48

= (2 x^{3} + 3 x^{2}) + (- 32 x - 48)

Factor out

x^{2}

from

2 x^{3} + 3 x^{2} : x^{2} (2 x + 3)

Factor out

- 16

from

- 32 x - 48 : - 16 (2 x + 3)

= x^{2} (2 x + 3) - 16 (2 x + 3)

Factor out common term

2 x + 3

= (2 x + 3) (x^{2} - 16)

Factor

x^{2} - 16 : (x + 4) (x - 4)

= (2 x + 3) (x + 4) (x - 4)

6 - 4 i

\frac{8 + x}{8 - x} \geq 1

\frac{x}{6} - \frac{7}{3} \leq \frac{x}{3} + 1

x^{2} + 10 x + 25 = 11

8 (x - 1) - 2 x = - (x + 50)

What is factor 2x^3+3x^2-32x-48 ?
The solution to factor 2x^3+3x^2-32x-48 is (2x+3)(x+4)(x-4)