What are the solutions to the equation sqrt(29)=5^2+x^2 ?

The solutions to the equation sqrt(29)=5^2+x^2 are x=sqrt(-\sqrt{29)+25}i,x=-sqrt(-\sqrt{29)+25}i

Find the zeros of sqrt(29)=5^2+x^2

The zeros of sqrt(29)=5^2+x^2 are x=sqrt(-\sqrt{29)+25}i,x=-sqrt(-\sqrt{29)+25}i

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29 = 5^{2} + x^{2}

x = - 29 + 25 i, x = - - 29 + 25 i

Solution steps

29 = 5^{2} + x^{2}

Switch sides

5^{2} + x^{2} = 29

Move

5^{2}

to the right side

x^{2} = 29 - 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 29 - 25, x = - 29 - 25

29 - 25 = - 29 + 25 i

- 29 - 25 = - - 29 + 25 i

x = - 29 + 25 i, x = - - 29 + 25 i

3 k^{3} + k^{2} - 4 k

\frac{24 !}{5 ! 19 !}

p^{6} + 40 p^{3} q + 400 q^{2}

m^{2} - 4 m = 140

x^{2} - 22 x + 40

What are the solutions to the equation sqrt(29)=5^2+x^2 ?
The solutions to the equation sqrt(29)=5^2+x^2 are x=sqrt(-\sqrt{29)+25}i,x=-sqrt(-\sqrt{29)+25}i
Find the zeros of sqrt(29)=5^2+x^2
The zeros of sqrt(29)=5^2+x^2 are x=sqrt(-\sqrt{29)+25}i,x=-sqrt(-\sqrt{29)+25}i