What is (x-3)(x+3)>= (x+5)^2 ?

The solution to (x-3)(x+3)>= (x+5)^2 is x<=-17/5

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(x-3)(x+3)>= (x+5)^2

(x - 3) (x + 3) \geq (x + 5)^{2}

x \leq - \frac{17}{5}

Interval Notation

(- \infty, - \frac{17}{5}]

Decimal Notation

x \leq - 3.4

Solution steps

(x - 3) (x + 3) \geq (x + 5)^{2}

Rewrite in standard form

- 5 x - 17 \geq 0

Move

17

to the right side

- 5 x \geq 17

Multiply both sides by

- 1

5 x \leq - 17

Divide both sides by

5

x \leq - \frac{17}{5}

∣ x + 5 ∣ \geq 3

∣ x ∣ = - 8

x^{2} - 3 x y - 10 y^{2}

(5^{- 1})^{2}

0 = - 4 x^{2} - 10 x - 5