What are the solutions to the equation 16t^2+11t-205=0 ?

The solutions to the equation 16t^2+11t-205=0 are t=(-11+sqrt(13241))/(32),t=(-11-sqrt(13241))/(32)

Find the zeros of 16t^2+11t-205=0

The zeros of 16t^2+11t-205=0 are t=(-11+sqrt(13241))/(32),t=(-11-sqrt(13241))/(32)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 t^{2} + 11 t - 205 = 0

t = \frac{- 11 + 13241}{32}, t = \frac{- 11 - 13241}{32}

Decimal Notation

t = 3.25217 \dots, t = - 3.93967 \dots

Solution steps

16 t^{2} + 11 t - 205 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 16 ( - 205 )}{2 \cdot 16}

1 1^{2} - 4 \cdot 16 (- 205) = 13241

t_{1, 2} = \frac{- 11 \pm 13241}{2 \cdot 16}

Separate the solutions

t_{1} = \frac{- 11 + 13241}{2 \cdot 16}, t_{2} = \frac{- 11 - 13241}{2 \cdot 16}

t = \frac{- 11 + 13241}{2 \cdot 16} : \frac{- 11 + 13241}{32}

t = \frac{- 11 - 13241}{2 \cdot 16} : \frac{- 11 - 13241}{32}

The solutions to the quadratic equation are:

t = \frac{- 11 + 13241}{32}, t = \frac{- 11 - 13241}{32}

m < \frac{1}{2} (11 - 18)

1 < 3 x^{4}

j^{2} + 20 j + 19

\frac{4}{5} v < \frac{7}{15}

\frac{7}{2} (3)

What are the solutions to the equation 16t^2+11t-205=0 ?
The solutions to the equation 16t^2+11t-205=0 are t=(-11+sqrt(13241))/(32),t=(-11-sqrt(13241))/(32)
Find the zeros of 16t^2+11t-205=0
The zeros of 16t^2+11t-205=0 are t=(-11+sqrt(13241))/(32),t=(-11-sqrt(13241))/(32)