What are the solutions to the equation w^2+9w+14=0 ?

The solutions to the equation w^2+9w+14=0 are w=-2,w=-7

Find the zeros of w^2+9w+14=0

The zeros of w^2+9w+14=0 are w=-2,w=-7

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w^{2} + 9 w + 14 = 0

w = - 2, w = - 7

Solution steps

w^{2} + 9 w + 14 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 14 = 5

w_{1, 2} = \frac{- 9 \pm 5}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 9 + 5}{2 \cdot 1}, w_{2} = \frac{- 9 - 5}{2 \cdot 1}

w = \frac{- 9 + 5}{2 \cdot 1} : - 2

w = \frac{- 9 - 5}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

w = - 2, w = - 7

(i - 2)^{2} (i + 2)

3 ∣ x - 4 ∣ + 5 \leq 17

\frac{( ( 1.17 ) ( 2.03 ) ^{2} )}{2} + 4.4793735

\frac{6}{11} \cdot \frac{7}{3}

- 2 + 3 (3) \geq \frac{1}{4}

What are the solutions to the equation w^2+9w+14=0 ?
The solutions to the equation w^2+9w+14=0 are w=-2,w=-7
Find the zeros of w^2+9w+14=0
The zeros of w^2+9w+14=0 are w=-2,w=-7