What are the solutions to the equation x^2+16x+58=0 ?

The solutions to the equation x^2+16x+58=0 are x=-8+sqrt(6),x=-8-sqrt(6)

Find the zeros of x^2+16x+58=0

The zeros of x^2+16x+58=0 are x=-8+sqrt(6),x=-8-sqrt(6)

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x^{2} + 16 x + 58 = 0

x = - 8 + 6, x = - 8 - 6

Decimal Notation

x = - 5.55051 \dots, x = - 10.44948 \dots

Solution steps

x^{2} + 16 x + 58 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 58}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 58 = 26

x_{1, 2} = \frac{- 16 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 6}{2 \cdot 1}

x = \frac{- 16 + 2 6}{2 \cdot 1} : - 8 + 6

x = \frac{- 16 - 2 6}{2 \cdot 1} : - 8 - 6

The solutions to the quadratic equation are:

x = - 8 + 6, x = - 8 - 6

x^{2} = 512

\frac{8.95 \cdot 1 0 ^{5}}{1860}

x^{2} + 3 x + 5 > 0

299

2 X + 3 X - 5 + 8 + X = 2 (2 X + 5) + 15

What are the solutions to the equation x^2+16x+58=0 ?
The solutions to the equation x^2+16x+58=0 are x=-8+sqrt(6),x=-8-sqrt(6)
Find the zeros of x^2+16x+58=0
The zeros of x^2+16x+58=0 are x=-8+sqrt(6),x=-8-sqrt(6)