What are the solutions to the equation 2x(x+5)+10=0 ?

The solutions to the equation 2x(x+5)+10=0 are x=(-5+sqrt(5))/2 ,x=-(5+sqrt(5))/2

Find the zeros of 2x(x+5)+10=0

The zeros of 2x(x+5)+10=0 are x=(-5+sqrt(5))/2 ,x=-(5+sqrt(5))/2

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2 x (x + 5) + 10 = 0

x = \frac{- 5 + 5}{2}, x = - \frac{5 + 5}{2}

Decimal Notation

x = - 1.38196 \dots, x = - 3.61803 \dots

Solution steps

2 x (x + 5) + 10 = 0

Expand

2 x (x + 5) + 10 : 2 x^{2} + 10 x + 10

2 x^{2} + 10 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 10 = 25

x_{1, 2} = \frac{- 10 \pm 2 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 2 5}{2 \cdot 2}, x_{2} = \frac{- 10 - 2 5}{2 \cdot 2}

x = \frac{- 10 + 2 5}{2 \cdot 2} : \frac{- 5 + 5}{2}

x = \frac{- 10 - 2 5}{2 \cdot 2} : - \frac{5 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 5}{2}, x = - \frac{5 + 5}{2}

\frac{( 1 9 ^{9} ) ^{7} \times 1 9 ^{8}}{1 9 ^{86}}

∣ x + 2 ∣ > ∣ x - 3 ∣ + 1

4 x^{2} - 4 x = - 21

∣ 3 x - 7 ∣ \geq 8

x^{2} + 5 > 0

What are the solutions to the equation 2x(x+5)+10=0 ?
The solutions to the equation 2x(x+5)+10=0 are x=(-5+sqrt(5))/2 ,x=-(5+sqrt(5))/2
Find the zeros of 2x(x+5)+10=0
The zeros of 2x(x+5)+10=0 are x=(-5+sqrt(5))/2 ,x=-(5+sqrt(5))/2