What are the solutions to the equation 4x^2-4x=-21 ?

The solutions to the equation 4x^2-4x=-21 are x= 1/2+sqrt(5)i,x= 1/2-sqrt(5)i

Find the zeros of 4x^2-4x=-21

The zeros of 4x^2-4x=-21 are x= 1/2+sqrt(5)i,x= 1/2-sqrt(5)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 4 x = - 21

x = \frac{1}{2} + 5 i, x = \frac{1}{2} - 5 i

Solution steps

4 x^{2} - 4 x = - 21

Move

21

to the left side

4 x^{2} - 4 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 21}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 21 : 85 i

x_{1, 2} = \frac{- ( - 4 ) \pm 8 5 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 5 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 8 5 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 8 5 i}{2 \cdot 4} : \frac{1}{2} + 5 i

x = \frac{- ( - 4 ) - 8 5 i}{2 \cdot 4} : \frac{1}{2} - 5 i

The solutions to the quadratic equation are:

x = \frac{1}{2} + 5 i, x = \frac{1}{2} - 5 i

∣ 3 x - 7 ∣ \geq 8

x^{2} + 5 > 0

12 x^{2} + 5 x - 3 > 0

\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}

2 x^{2} - 4 x + 5 = 6

What are the solutions to the equation 4x^2-4x=-21 ?
The solutions to the equation 4x^2-4x=-21 are x= 1/2+sqrt(5)i,x= 1/2-sqrt(5)i
Find the zeros of 4x^2-4x=-21
The zeros of 4x^2-4x=-21 are x= 1/2+sqrt(5)i,x= 1/2-sqrt(5)i