en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12x^2+5x-3>0

Solution

12 x^{2} + 5 x - 3 > 0

Solution

x < - \frac{3}{4} or x > \frac{1}{3}

+2

Interval Notation

(- \infty, - \frac{3}{4}) \cup (\frac{1}{3}, \infty)

Decimal Notation

x < - 0.75 or x > 0.33333 \dots

Solution steps

12 x^{2} + 5 x - 3 > 0

Factor

12 x^{2} + 5 x - 3 : (3 x - 1) (4 x + 3)

(3 x - 1) (4 x + 3) > 0

Identify the intervals

x < - \frac{3}{4} or x > \frac{1}{3}

Popular Examples

simplify 1/2+1/3+1/4+1/5+1/6 simplify

\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}

2 x^{2} - 4 x + 5 = 6

simplify 7/45*9/10 simplify

\frac{7}{45} \cdot \frac{9}{10}

factor 4x^2+24x+36 factor

4 x^{2} + 24 x + 36

10 t - 1.86 t^{2} = 0

Frequently Asked Questions (FAQ)

What is 12x^2+5x-3>0 ?
The solution to 12x^2+5x-3>0 is x<-3/4 \lor x> 1/3