What are the solutions to the equation x^2+6x+12=0 ?

The solutions to the equation x^2+6x+12=0 are x=-3+sqrt(3)i,x=-3-sqrt(3)i

Find the zeros of x^2+6x+12=0

The zeros of x^2+6x+12=0 are x=-3+sqrt(3)i,x=-3-sqrt(3)i

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x^{2} + 6 x + 12 = 0

x = - 3 + 3 i, x = - 3 - 3 i

Solution steps

x^{2} + 6 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 12 : 23 i

x_{1, 2} = \frac{- 6 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 3 i}{2 \cdot 1}

x = \frac{- 6 + 2 3 i}{2 \cdot 1} : - 3 + 3 i

x = \frac{- 6 - 2 3 i}{2 \cdot 1} : - 3 - 3 i

The solutions to the quadratic equation are:

x = - 3 + 3 i, x = - 3 - 3 i

\frac{0.9 - 2}{( 0.9 - 1 ) ^{2}}

2 m^{2} - m - 15

lo g_{5} (6) + lo g_{5} (2) x^{2} = lo g_{5} (48)

64 a^{2} b - 16 a^{3} + 18 a^{2} b - 9

(\frac{7}{25})^{2} + (\frac{24}{25})^{2}

What are the solutions to the equation x^2+6x+12=0 ?
The solutions to the equation x^2+6x+12=0 are x=-3+sqrt(3)i,x=-3-sqrt(3)i
Find the zeros of x^2+6x+12=0
The zeros of x^2+6x+12=0 are x=-3+sqrt(3)i,x=-3-sqrt(3)i