What are the solutions to the equation -3x^2-6x=-1 ?

The solutions to the equation -3x^2-6x=-1 are x=-(3+2sqrt(3))/3 ,x=(2sqrt(3)-3)/3

Find the zeros of -3x^2-6x=-1

The zeros of -3x^2-6x=-1 are x=-(3+2sqrt(3))/3 ,x=(2sqrt(3)-3)/3

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- 3 x^{2} - 6 x = - 1

x = - \frac{3 + 2 3}{3}, x = \frac{2 3 - 3}{3}

Decimal Notation

x = - 2.15470 \dots, x = 0.15470 \dots

Solution steps

- 3 x^{2} - 6 x = - 1

Move

1

to the left side

- 3 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) \cdot 1}{2 ( - 3 )}

(- 6)^{2} - 4 (- 3) \cdot 1 = 43

x_{1, 2} = \frac{- ( - 6 ) \pm 4 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4 3}{2 ( - 3 )}, x_{2} = \frac{- ( - 6 ) - 4 3}{2 ( - 3 )}

x = \frac{- ( - 6 ) + 4 3}{2 ( - 3 )} : - \frac{3 + 2 3}{3}

x = \frac{- ( - 6 ) - 4 3}{2 ( - 3 )} : \frac{2 3 - 3}{3}

The solutions to the quadratic equation are:

x = - \frac{3 + 2 3}{3}, x = \frac{2 3 - 3}{3}

3 x - 2 \leq 2 x - 1

\frac{1}{5} \times \frac{4}{5} + \frac{4}{5} \times \frac{1}{5}

\frac{p}{20} + 14 = 18

0 = - 2 x^{2} + 20

38.6 \cdot \frac{1}{15.999 ( 2 )}

What are the solutions to the equation -3x^2-6x=-1 ?
The solutions to the equation -3x^2-6x=-1 are x=-(3+2sqrt(3))/3 ,x=(2sqrt(3)-3)/3
Find the zeros of -3x^2-6x=-1
The zeros of -3x^2-6x=-1 are x=-(3+2sqrt(3))/3 ,x=(2sqrt(3)-3)/3