What is (-9n^8)/(27n^{10)} ?

The solution to (-9n^8)/(27n^{10)} is -1/(3n^2)

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simplify (-9n^8)/(27n^{10)}

simplify

\frac{- 9 n ^{8}}{27 n ^{10}}

- \frac{1}{3 n ^{2}}

Solution steps

\frac{- 9 n ^{8}}{27 n ^{10}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{9 n ^{8}}{27 n ^{10}}

Cancel the common factor:

9

= \frac{n ^{8}}{3 n ^{10}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{n ^{8}}{n ^{10}} = \frac{1}{n ^{10 - 8}}

= \frac{1}{3 n ^{10 - 8}}

Subtract the numbers:

10 - 8 = 2

= - \frac{1}{3 n ^{2}}

8^{- 5}

i^{- 7}

20 x y + 12 x + 15 y + 9

\frac{x}{10} - \frac{7}{4} = 3 x - \frac{2 x}{5}

x^{2} + 18 x + 81 = 0