What are the solutions to the equation 5x^2+6x-7=0 ?

The solutions to the equation 5x^2+6x-7=0 are x=(-3+2sqrt(11))/5 ,x=-(3+2sqrt(11))/5

Find the zeros of 5x^2+6x-7=0

The zeros of 5x^2+6x-7=0 are x=(-3+2sqrt(11))/5 ,x=-(3+2sqrt(11))/5

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5 x^{2} + 6 x - 7 = 0

x = \frac{- 3 + 2 11}{5}, x = - \frac{3 + 2 11}{5}

Decimal Notation

x = 0.72664 \dots, x = - 1.92664 \dots

Solution steps

5 x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 7 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 7) = 411

x_{1, 2} = \frac{- 6 \pm 4 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 4 11}{2 \cdot 5}, x_{2} = \frac{- 6 - 4 11}{2 \cdot 5}

x = \frac{- 6 + 4 11}{2 \cdot 5} : \frac{- 3 + 2 11}{5}

x = \frac{- 6 - 4 11}{2 \cdot 5} : - \frac{3 + 2 11}{5}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2 11}{5}, x = - \frac{3 + 2 11}{5}

\frac{( 4 x ^{- 3} y ^{5} ) ^{3}}{( 16 x ^{2} y ^{- 2} ) ^{- 4}}

x^{2} - 5 x + 15 = x (x - 3) - 14 + 5 (x - 2) + 3 (13 - 2 x)

x^{2} = 6 x + 91

\frac{1}{2} 12 - \frac{1}{3} 18 + \frac{3}{4} 48 + \frac{1}{6} 72

2 a^{2} - 8 a

What are the solutions to the equation 5x^2+6x-7=0 ?
The solutions to the equation 5x^2+6x-7=0 are x=(-3+2sqrt(11))/5 ,x=-(3+2sqrt(11))/5
Find the zeros of 5x^2+6x-7=0
The zeros of 5x^2+6x-7=0 are x=(-3+2sqrt(11))/5 ,x=-(3+2sqrt(11))/5